HUNGARIAN LENTIL STEW

Hungarian Lentil Stew image

Provided by Leslie Kaufman

Categories dinner, easy, one pot, soups and stews, main course

Time 1h

Yield 6 to 8 servings

Number Of Ingredients 13

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Ingredients

1 1-pound bag brown lentils
1 1/2 tablespoons vegetable oil
1 medium onion, finely chopped
6 cloves garlic, minced
2 tablespoons sweet Hungarian paprika
3 bay leaves
2 cups whole-fat sour cream
3 1/2 tablespoons all-purpose flour
2 tablespoons milk
1/2 teaspoon salt, or as needed
1 tablespoon light brown sugar
2 tablespoons brown mustard, or as needed
2 tablespoons fresh lemon juice, or as needed

Steps:

If desired, place lentils in a bowl with water to cover, and soak overnight; this step may be skipped, but makes lentils more digestible.
Place a large (5- to 6-quart) saucepan over medium-low heat, and add oil and onion. Sauté until tender, 1 to 2 minutes. Add garlic and paprika, and sauté until garlic is fragrant, 1 minute more. Add lentils, 8 cups water and bay leaves. Increase heat to bring to a boil, then reduce heat to low. Cover and simmer, stirring occasionally, until lentils are tender, about 50 minutes; add water as needed if mixture seems too thick.
When lentils are tender, in a small bowl stir together sour cream, flour and milk. Add to lentils and simmer 2 to 3 minutes. Add salt, brown sugar, mustard and lemon juice, adjusting amounts as needed for a slightly piquant flavor. If desired, remove and discard bay leaves. Serve hot.

Nutrition Facts : @context http, Calories 370, UnsaturatedFat 6 grams, Carbohydrate 45 grams, Fat 15 grams, Fiber 7 grams, Protein 16 grams, SaturatedFat 7 grams, Sodium 221 milligrams, Sugar 5 grams, TransFat 0 grams